4.0 g of NaOH are dissolved per litre of the solution at 298 K. Calculate the $p H$ of the solution.

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Solution

$4 g m$ of NOOH $= \frac{4}{40} =$ $0.1 M$ NOOH
POH $= - log [O H^{-}] = - log [0.1] = + 1$
POH $= 1$
We know $,$ $p H + p O H = 14$
$p H = 13.$
We know,
$p H + p O H = 14$
$p H + 1 = 14$
$∴ p H = 13$

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4.0 g of NaOH are dissolved per litre of the solution at 298 K. Calculate the pH of the solution.

4gm of NOOH =440= 0.1M NOOHPOH=−log[OH−]=−log[0.1]=+1POH=1We know, pH+pOH=14pH=13.We know, pH+pOH=14pH+1=14∴pH=13

4.0 g of NaOH are dissolved per litre of the solution at 298 K. Calculate the $p H$ of the solution.

$4 g m$ of NOOH $= \frac{4}{40} =$ $0.1 M$ NOOH
POH $= - log [O H^{-}] = - log [0.1] = + 1$
POH $= 1$
We know $,$ $p H + p O H = 14$
$p H = 13.$
We know,
$p H + p O H = 14$
$p H + 1 = 14$
$∴ p H = 13$