4.0 kg of a gas occupies 22 . 4 litres at NTP. The specific heat capacity of the gas at constant volume is 5.0 $J K^{- 1}$ $m o l^{- 1}$ If the speed of sound in this gas at NTP is 952 $m s^{- 1}$ then the heat capacity at constant pressure is (Take gas constant R = 8.3 $J K^{- 1}$ $m o l^{- 1}$

8.5 {J K}^{- 1} {m o l}^{- 1}

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8.0 {J K}^{- 1} {m o l}^{- 1}

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7.5 {J K}^{- 1} {m o l}^{- 1}

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7.0 {J K}^{- 1} {m o l}^{- 1}

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Solution

The correct option is B $8.0 {J K}^{- 1} {m o l}^{- 1}$
$\begin{matrix} M o l e c u l a r m a s s M = 4.0 g v_{s o u n d} = \sqrt{\frac{λ R T}{M}} \Rightarrow λ = \frac{M v^{2}}{T} = 1.6 S o, C_{p} = λ C_{v} = 1.6 \times 5.0 = 8.0 J K^{- 1} m o l^{- 1} \end{matrix}$
Hence,
option $(B)$ is correct answer.

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Similar questions

4.0 g of a gas occupies 22.4L at NTP. The specific heat capacity of the gas at constant volume is 5.0 JK-1mol-1. If the speed of sound in the gas at NTP is 952 ms-1, then the heat capacity at constant pressure is.

(Take gas constant R=8.3 JK-1mol-1)

Q. 4.0 g of a gas occupies 22.4 litres at NTP. The specific heat capacity of the gas at constant volume is

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4.0 kg of a gas occupies 22 . 4 litres at NTP. The specific heat capacity of the gas at constant volume is 5.0 JK−1 mol−1 If the speed of sound in this gas at NTP is 952 ms−1 then the heat capacity at constant pressure is (Take gas constant R = 8.3 JK−1 mol−1

The correct option is B 8.0JK−1mol−1MolecularmassM=4.0gvsound=√λRTM⇒λ=Mv2T=1.6So,Cp=λCv=1.6×5.0=8.0JK−1mol−1Hence,option (B) is correct answer.

4.0 kg of a gas occupies 22 . 4 litres at NTP. The specific heat capacity of the gas at constant volume is 5.0 $J K^{- 1}$ $m o l^{- 1}$ If the speed of sound in this gas at NTP is 952 $m s^{- 1}$ then the heat capacity at constant pressure is (Take gas constant R = 8.3 $J K^{- 1}$ $m o l^{- 1}$