Question

$4_1{H}^1{\to }_{2}H{e}^4+2e^{+}+26MeV$
The above reaction represents

• A. Fusion
• B. Fission
• C. $\beta$-decay
• D. $\gamma$-decay

Answer 1

The correct option is A Fusion

Overall reaction of fusion is given below
$4_1^{1}H{\to }_2^{4}He+2{(}_1^{0}e)+26MeV$

Reaction of fission is
${}_{92}^{235}U{+}_0^{1}n{\to }_{56}^{141}Ba{+}_{36}^{92}Kr+3_0^{1}n+Energy$

$\beta$- decay equation is
${}_Z^{A}X{\underset{}{\overset{minus{e}^{-}}{\to }}}_{Z+1}^{A}Y$

${\rm Y}$ - decay equation is
${}_Z^{A}X\to -Z^{A}X$