$42 A$
$+ 2 A 5 - ------ -$
$A 02$
Find the value of $A$

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Solution

$A + 5 = 2$ and $A$ cannot be negative and a $2 -$ digit number.
$∴ A = 7 ∵ 7 + 5 = 12$
$1$ is carried to the next place (ten's place)
then $2 + A + 1 = 0$ or $2 + 7 + 1 = 10$
Again $1$ is carried to the next place(hundred's place)
$4 + 2 + 1 = 7$
Hence the value of $A = 7$

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