Question

4 *√28/ 3 *√7 / ₃√7 [cube root 7]

Answer 1

$$\begin{gathered} Assumingyourquestionas, \\ \frac{{\displaystyle \frac{4\sqrt{28}}{3\sqrt{7}}}}{\sqrt[3]{7}}=\frac{4\sqrt{28}}{3\sqrt{7}}\times \frac{1}{\sqrt[3]{7}}=\frac{4}{3}\times \sqrt{\frac{28}{7}}\times \frac{1}{\sqrt[3]{7}} \\ =\frac{4}{3}\times \sqrt{4}\times \frac{1}{\sqrt[3]{7}}=\frac{8}{3}\times \frac{1}{\sqrt[3]{7}} \\ =\frac{8}{3\sqrt[3]{7}} \end{gathered}$$