$4.28 g$ of $N a O H$ is dissolved in water and the solution is made to $250 c c$ . What will be the molarity of the solution?

0.615 m o l L^{- 1}

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0.428 m o l L^{- 1}

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0.99 m o l L^{- 1}

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0.301 m o l L^{- 1}

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Solution

The correct option is A $0.428 m o l L^{- 1}$
Molarity, M= $\frac{n u m b e r o f m o l e s}{v o l u m e o f s o l u t i o n}$
$M = \frac{n}{V}$
Number of moles, n= $\frac{m a s s}{m o l a r m a s s}$
Molar mass of $N a O H$ =40 g/mole
Mass=4.28g
$n = \frac{4.28}{40} = 0.107$ mole
Volume, V=250 cc=0.25 L
$∴ M = 0.107 / 0.25 = 0.428 m o l e / L$

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