4.5 g of aluminium (at. mass 27 amu) is deposited at cathode from Al3+ solution by a certain quantity of electric charge. The volume of hydrogen produced at STP from H+ ions in solution by the same quantity of electric charge will be:
A
44.8L
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B
11.2L
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C
22.4L
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D
5.6L
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Solution
The correct option is D 5.6L No. of moles of Aluminium deposited =4.527=16moles
2Al⟶2Al3++6e−
6H++6e−⟶3H2
⟹2Al+6H+⟶3H2+2Al3+
2moles of Aluminium produce 3moles of hydrogen. So, 2moles of Al⟶3moles of H2