wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

4.5 moles each of hydrogen and iodine are heated in a sealed 10 litre vessel. At equilibrium 3 moles of hydrogen iodide was found. The equilibrium constant for H2(g)+I2(g)2HI(g)
1) 1 2) 10 3) 5 4) 0.33

Open in App
Solution

The correct option is 1

We have,

4.5 moles each of hydrogen and iodine which is heated in a sealed 10litre vessel.

H2(g)+I2(g)2HI(g)

Since 1 mole of H2 and one mole of I2 combine to give 2 moles
of HI then 3 moles of HI would be formed by ICE table,

KC for the reaction at equlibrium is :

=[HI]2[H2][I2]

=[3]2[3][3]

=1


960821_1036020_ans_0cf232a95a1c4af9bdb4383b01b4e39e.PNG

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equilibrium Constants
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon