Question

$4.5$ moles of calcium carbonate are reacted with dilute hydrochloric acid.

(a) Write the equation for the reaction.

Answer 1

Chemical Equation

• A chemical change can be represented through a chemical equation using formulae and symbols.
• It specifies the identity or composition of compounds or elements that act as reactants and products.

Chemical Reaction

• The given reactants are Calcium carbonate $\left({\mathrm{CaCO}}_3\right)$ and dilute hydrochloric acid $\left(\mathrm{HCl}\right)$.
• Calcium carbonate reacts with dilute hydrochloric acid and results in the formation of Calcium chloride$\left({\mathrm{CaCl}}_2\right)$, water $\left({\mathrm{H}}_2\mathrm{O}\right)$ along with the liberation of carbon dioxide $\left({\mathrm{CO}}_2\right)$.
• The balanced chemical equation is as follows:

${\mathrm{CaCO}}_3\left(\mathrm{s}\right)+\mathrm{dil}.2\mathrm{HCl}\left(\mathrm{aq}\right)\to {\mathrm{CaCl}}_2\left(\mathrm{s}\right)+{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)+{\mathrm{CO}}_2\left(\mathrm{g}\right)$