4.5 moles of calcium carbonate are reacted with dilute hydrochloric acid
How many moles of HCl are used in this reaction?

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Solution

1 mole of CaCO2 uses 2 mole of HCl.
hence,
4.5 moles of CaCO2 will use =
2*4.5=9 moles of HCl

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Similar questions

4.5 moles of calcium carbonate are reacted with dilute hydrochloric acid.
(i) Write the equation for the reaction.
(ii) What is the mass of 4.5 moles of calcium carbonate? (Relative molecular mass of calcium carbonate is 100).
(iii) What is the volume of carbon dioxide liberated at stp?
(iv) What mass of calcium chloride is formed? (Relative molecular mass of calcium chloride is 111)
(v) How many moles of HCl are used in this reaction?

4.5 moles of calcium carbonate are reacted with dilute hydrochloric acid.

What is the mass of 4.5 moles of calcium carbonate? (Relative molecular mass of calcium carbonate is 100).

4.5 moles of calcium carbonate are reacted with dilute hydrochloric acid.

What is the volume of carbon dioxide liberated at STP?

4.5 moles of calcium carbonate are reacted with dilute hydrochloric acid.

What mass of calcium chloride is formed? [Relative molecular mass of calcium chloride is 111].

Q. How many grams of

C O_{2}

can be prepared from

150

grams of calcium carbonate (

C a C O_{3}

) reacting with an excess of hydrochloric (

H C l

) acid solution?

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4.5 moles of calcium carbonate are reacted with dilute hydrochloric acid How many moles of HCl are used in this reaction?

1 mole of CaCO2 uses 2 mole of HCl. hence, 4.5 moles of CaCO2 will use = 2*4.5=9 moles of HCl

4.5 moles of calcium carbonate are reacted with dilute hydrochloric acid
How many moles of HCl are used in this reaction?

1 mole of CaCO2 uses 2 mole of HCl.
hence,
4.5 moles of CaCO2 will use =
2*4.5=9 moles of HCl