4.5 moles of calcium carbonate are reacted with dilute hydrochloric acid.

What is the volume of carbon dioxide liberated at STP?

100.8 litres

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150 litres

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125.3 litres

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90.6 litres

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115 litres

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Solution

The correct option is A
100.8 litres

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Similar questions

4.5 moles of calcium carbonate are reacted with dilute hydrochloric acid.
(i) Write the equation for the reaction.
(ii) What is the mass of 4.5 moles of calcium carbonate? (Relative molecular mass of calcium carbonate is 100).
(iii) What is the volume of carbon dioxide liberated at stp?
(iv) What mass of calcium chloride is formed? (Relative molecular mass of calcium chloride is 111)
(v) How many moles of HCl are used in this reaction?

4.5 moles of calcium carbonate are reacted with dilute hydrochloric acid.

What is the mass of 4.5 moles of calcium carbonate? (Relative molecular mass of calcium carbonate is 100).

4.5 moles of calcium carbonate are reacted with dilute hydrochloric acid.

What mass of calcium chloride is formed? [Relative molecular mass of calcium chloride is 111].

Q. 4.5 moles of calcium carbonate are reacted with dilute hydrochloric acid
How many moles of HCl are used in this reaction?

Q. What is the volume (in L) of carbon dioxide liberated at STP when

2.12

grams of sodium carbonate (mol. wt.

= 106

) is treated with excess dilute

H C l

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4.5 moles of calcium carbonate are reacted with dilute hydrochloric acid. What is the volume of carbon dioxide liberated at STP?

The correct option is A 100.8 litres

4.5 moles of calcium carbonate are reacted with dilute hydrochloric acid.

What is the volume of carbon dioxide liberated at STP?

The correct option is A
100.8 litres