4/5 of kg's apples were used on monday .the next day 1/3 of what was left was used. Weight in kg of apples left now is ?

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Solution

Dear student
$A p p l e u s e d o n M o n d a y = \frac{4}{5} k g R e m a i n i n g a p p l e = 1 - \frac{4}{5} k g = \frac{1}{5} k g A p p l e u s e d n e x t d a y = \frac{1}{5} \times \frac{1}{3} k g = \frac{1}{15} k g A p p l e u s e d b o t h t h e d a y s = \frac{4}{5} + \frac{1}{15} = \frac{13}{15} k g R e m a i n i n g a p p l e = 1 - \frac{13}{15} k g = \frac{2}{15} k g$
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4/5 of kg's apples were used on monday .the next day 1/3 of what was left was used. Weight in kg of apples left now is ?

Dear student Apple used on Monday=45kgRemaining apple=1-45kg=15kgApple used next day=15×13kg=115kgApple used both the days=45+115=1315kgRemaining apple=1-1315kg=215kg Regards