$4^{61} + 4^{62} + 4^{63} + 4^{64}$ is divisible by:

3

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10

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11

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13

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Solution

The correct option is B $10$
$4^{61} + 4^{62} + 4^{63} + 4^{64}$

$= 4^{61} (1 + 4 + 4^{2} + 4^{3})$

$= 4^{61} \times 85$

$= 4^{60} \times 4 \times 85$

$= 4^{60} \times 20 \times 17$

Now $20$ is divisible by $10$ .

Therefore Option B is correct.

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