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Charge Behaviour

4 7 Be captur...

Question

$_{4}^{7} B e$ captures a $K$ -electron into its nucleus. What will be the mass number of resulting nuclide?

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Solution

$_{4}^{7} B e +_{- 1}^{0} e \to_{3}^{7} L i$
Hence the mass number of resulting nuclide i.e $L i = 7$ .

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Similar questions

_{4}^{7}

captures a K electron into its nucleus. What is the mass number and atomic number of the nuclide formed?

_{4}^{7}

captures a K electron into its nucleus. What is the atomic number and atomic mass of the nuclide formed?

_{56}^{133} B a + e^{-} ⟶

_{55}^{133} C s + X

-ray.
It is an example of

K

-electron capture. Reason: Atomic number of daughter nuclide decreases by one unit in

K

-electron capture.

Q. In an electron capture, electron from K shell falls into a nucleus to undergo beta decay.

_{56}^{133} B e + e^{-} \to_{55}^{133} C s + X - r a y

It is a process of K-electron capture.. .
(R) The atomic number decreases by one unit as a result of K-capture.

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