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Question

4.86×10x iron atoms are present in a stainless steel ball bearing having a radius of 0.254 cm?The stainless steel contains 85.6% Fe, by mass and has density 7.75 g/mL.
So, the value of x is......

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Solution

Volume of ball d=4/3πr3
So, mass of iron =dV0.856
So, number of iron atoms in ball =dV0.856No/56 = 4.86×1021
Therefore, the value of x is 21.

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