4.9 gm sulphuric acid contains 0.1gm of hydrogen,1.6gm of sulfur, and the rest of oxygen. Calculate the mass percent composition of all elements of sulphuric acid.

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Solution

Definition of percentage composition of the compound
The ratio of the amount of each element to the total amount of individual elements present in the compound is multiplied by 100. Here, the quantity is measured in terms of grams of the elements present
We are given:
Mass of sample = 4.9 g
Mass of hydrogen = 0.1 g
Mass of sulfur = 1.6 g
Mass of oxygen = (4.9 - (0.1 + 1.6)) = 3.2 g
To calculate the mass percentage of calcium ions in milk, we use the equation:
$M a s s p e r c e n t o f e l e m e n t = \frac{m a s s o f e l e m e n t}{m a s s o f s a m p l e} \times 100$ …………………(1)
For hydrogen:
Putting values in equation 1, we get:
$M a s s p e r c e n t o f h y d r o g e n = \frac{0.1 g}{4.9 g} \times 100 = 2.04 %$
For oxygen:
Putting values in equation 1, we get:
$M a s s p e r c e n t o f h y d r o g e n = \frac{3.2 g}{4.9 g} \times 100 = 65.31 %$
For sulfur:
Putting values in equation 1, we get:
$M a s s p e r c e n t o f h y d r o g e n = \frac{1.6 g}{4.9 g} \times 100 = 32.65 %$
The mass percentage of hydrogen, sulfur and oxygen are 2.04 %, 32.65 % and 65.31 %

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Similar questions

When we do electrolysis we give dilute sulphuric acid ( CONTAINS HYDROGEN ) in the water.

When the electricity is passed, the hydrogen and oxygen are collected.

The hydrogen which is collected is of Sulphuric acid or of the water ? Why ?

4

100

80

H_{2} S O_{4}

1.96 g / m l

H_{2} S O_{4} = 98

S O_{3} + H_{2} O \to H_{2} S O_{4}

4.9 g

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