Question

(4/9)³ multiply (3/2)² divided (5/9)⁰.

Answer 1

Dear student,
$$\begin{gathered} \frac{{\left({\displaystyle \frac{4}{9}}\right)}^3\times {\left({\displaystyle \frac{3}{2}}\right)}^2}{{\left({\displaystyle \frac{5}{9}}\right)}^0}=\frac{{\left[{\left({\displaystyle \frac{2}{3}}\right)}^2\right]}^3\times {\left({\displaystyle \frac{3}{2}}\right)}^2}{{\left({\displaystyle \frac{5}{9}}\right)}^0}=\frac{{\left({\displaystyle \frac{2}{3}}\right)}^6\times {\left({\displaystyle \frac{2}{3}}\right)}^{-2}}{1}(as{a}^0=1and{\left(\frac{a}{b}\right)}^{-m}={\left(\frac{b}{a}\right)}^m) \\ ={\left(\frac{2}{3}\right)}^{6-2}={\left(\frac{2}{3}\right)}^4 \end{gathered}$$

Regards