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Question

4 Boys and 3 girls are standing in a straight line. Find the probability that girls and boys stand alternatively. Please answer as soon as possible.

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Solution

P(BGBGBGB)=47×36×35×24×23×12×11=4!3!7!=(3×2)(7×6×5)=135
That's because at first there are 4 boys out of 7 children.
Then there are 6 children left and 3 are girls so the next probability is 36, and so on.

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