4 boys and 3 girls are to be seated in a row in such a way that no 2 boys sit adjacent to each other. In how many different ways can it be done?
A
5040
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B
30
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C
144
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D
72
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E
None of these
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Solution
The correct option is C 144
3 girls can be seated in a row in 3! ways. Now, in the 4 gaps, 4 boys can be seated in 4! ways. Hence, the number of ways in which no two boys sit adjacent to each other = 3! × 4! = 6 × 24 =144