$4 (C_{51} H_{98} O_{6}) + 290 O_{2} \to 204 {CO}_{2} + 196 H_{2} O + Energy$

The R.Q. of the above equation is

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0.7

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1.45

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1.62

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Solution

The correct option is B 0.7
The ratio of the volume of ${CO}_{2}$ evolved to the volume of $O_{2}$ consumed in respiration is called the respiratory quotient (RQ) or respiratory ratio.
$R Q = \frac{V o l u m e o f C O_{2} e v o l v e d}{V o l u m e o f O_{2} c o n s u m e d}$
Here, RQ = $\frac{204}{290} = 0.703$

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Similar questions

4 (C_{51} H_{98} O_{6}) + 290 O_{2} \to 204 {CO}_{2} + 196 H_{2} O + Energy

2 (C_{51} H_{98} O_{6}) + 145 O_{2} \to

102 {CO}_{2} + 98 H_{2} O + energy

\frac{7}{100}

2 C_{51} H_{98} O_{6} + 146 O_{2} \to 102 C O_{2} + 98 H_{2} O

1 g

\frac{d^{2} x}{d t^{2}} + π^{2} x = 0

x

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