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Byju's Answer
Standard XII
Physics
Applying NLM along 3 Axis
4 charges are...
Question
4
charges are placed at follows:
−
2
q
at
(
a
,
0
)
q
at
(
0
,
−
a
)
−
2
q
at
(
−
a
,
0
)
3
q
at
(
0
,
a
)
The dipole moment of the configuration is
A
2
q
a
^
j
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B
3
q
a
^
j
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C
2
q
a
[
^
i
+
^
j
]
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D
None of these
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Solution
The correct option is
A
2
q
a
^
j
Net dipole moment
=
Σ
i
q
i
r
i
=
(
a
×
3
q
)
ˆ
j
+
(
−
2
q
a
)
ˆ
i
+
[
−
2
(
−
a
)
ˆ
i
]
+
q
(
−
a
)
ˆ
j
⟹
2
q
a
ˆ
j
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0
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