$4 {cos}^{2} x sin x - 2 {sin}^{2} x = 3 sin x$ .

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Solution

$sin x (4 {cos}^{2} x - 2 sin x - 3) = 0$
or $sin x (4 {sin}^{2} x + 2 sin x - 1) = 0$ .
Hence find different values of sinx and then x from values of sinx

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