4 eV is the energy of the incident photon and the work function in 2eV. What is the stopping potential
2V
4V
6V
2√2V
E=W0+eV0⇒4eV+eV0⇒V0=2 volt
4 eV is the energy of the incident photon and the work function in 2eV.What is the stopping potential
Photons of energy 6 eV are incident on a potassium surface of a work function 2.1 eV. What is the stopping potential?