$4 g$ atom of $A g$ contains:

108 g

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4 g

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432 g

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none of these

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Solution

The correct option is C $432 g$
$1 g$ atom of $A g$ implies $1$ mole of it
Hence, $4 g$ atom is $4$ moles of $A g$
$1$ moles of $A g = 108 g$
$∴ 4 g$ atom of $A g$ contains $4 \times 108 = 432 g$

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