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Standard XII

Chemistry

Equivalent Mass

4 g of a mixt...

Question

$4 g$ of a mixture of $N a C l$ and $N a_{2} C O_{3}$ were dissolved in water and volume made up to $250 m L$ . $15 m L$ of this solution required $50 m L$ of $N / 10 H C l$ for complete neutralisation. Calculate the percentage composition of the original mixture.

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Solution

Weight of $N a_{2} C O_{3} = a g$
Weight of $N a C l = b g$
$a + b = H$
Only $N a_{2} C O_{3}$ reacts
In $15$ ml, M eq of $N a_{2} C O_{3} =$ M eq of $H C l$
$\to 50 * \frac{1}{10} = 5$
M eq of $N a_{2} C O_{3}$ in $250$ ml = \frac {5 * 250} {25}$
$\to 50$

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4 g of a mixture of NaCl and Na2CO3 were dissolved in water and volume made up to 250 mL. 15 mL of this solution required 50 mL of N/10 HCl for complete neutralisation. Calculate the percentage composition of the original mixture.

Weight of Na2CO3=agWeight of NaCl=bga+b=HOnly Na2CO3 reacts In 15 ml, M eq of Na2CO3= M eq of HCl→50∗110=5M eq of Na2CO3 in 250ml = \frac {5 * 250} {25}$→50

$4 g$ of a mixture of $N a C l$ and $N a_{2} C O_{3}$ were dissolved in water and volume made up to $250 m L$ . $15 m L$ of this solution required $50 m L$ of $N / 10 H C l$ for complete neutralisation. Calculate the percentage composition of the original mixture.

Weight of $N a_{2} C O_{3} = a g$
Weight of $N a C l = b g$
$a + b = H$
Only $N a_{2} C O_{3}$ reacts
In $15$ ml, M eq of $N a_{2} C O_{3} =$ M eq of $H C l$
$\to 50 * \frac{1}{10} = 5$
M eq of $N a_{2} C O_{3}$ in $250$ ml = \frac {5 * 250} {25}$
$\to 50$