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Normality

4 g of NaOH a...

Question

$4$ g of NaOH and $9.8$ g of $H_{2} S O_{4}$ are mixed and volume is made $500 m l$ . The normality of the resulting solution will be:

0.4 N

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0.2 N

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0.02 N

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0.04 N

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Solution

The correct option is C $0.2 N$
Equivalent weight of $N a O H = \frac{M o l a r m a s s}{n - f a c t o r} = \frac{40}{1}$
Number of gram equivalent of solute $= \frac{G i v e n m a s s}{E q u i v a l e n t W e i g h t} = \frac{4}{40} = \frac{1}{10}$

$N o r m a l i t y = \frac{N u m b e r o f g r a m s e q u i v a l e n t o f s o l u t e}{v o l u m e o f s o l u t i o n (i n L)}$
$= \frac{1 / 10}{500 / 1000}$
$= \frac{1 \times 1000}{10 \times 500} = 0.2 N$

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