Question

$4$ gm of a metallic chloride contains $1.89$ g of the metal '$X$'. The empirical formula of the metallic chloride is:
[Atomic weight of $X=64,Cl=35.5$]

• A. $XCl$
• B. $X_{2}C{l}_2$
• C. $XC{l}_2$
• D. $X_{2}Cl$

Answer 1

The correct option is C $XC{l}_2$

Let, metal chloride is $MC{l}_x$.
Mass ratio of metal is $\frac{64}{(64+35.5x)}=1.89/4$
$x=2$
Metal chloride is $MC{l}_2$.