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Standard VI

Mathematics

Addition of Fractions

4 is added to...

Question

$4$ is added to a number and the sum is multiplied by $5$ . If $20$ is subtracted from the product and the difference is divided by $8$ , then the result is equal to $10$ . The number is:

8

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1

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20

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16

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Solution

The correct option is D $16$
Let the number is $x$
$\frac{(x + 4) \times 5 - 20}{8} = 10$
$(x + 4) \times 5 - 20 = 80$
$(x + 4) \times 5 = 100$
$(x + 4) = 100 \div 5$
$x + 4 = 20$
$x = 20 - 4$
$x = 16$

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4 is added to a number and the sum is multiplied by 5. If 20 is subtracted from the product and the difference is divided by 8, then the result is equal to 10. The number is:

The correct option is D 16Let the number is x (x+4)×5−208=10 (x+4)×5−20=80 (x+4)×5=100 (x+4)=100÷5 x+4=20 x=20−4 x=16

$4$ is added to a number and the sum is multiplied by $5$ . If $20$ is subtracted from the product and the difference is divided by $8$ , then the result is equal to $10$ . The number is:

The correct option is D $16$
Let the number is $x$
$\frac{(x + 4) \times 5 - 20}{8} = 10$
$(x + 4) \times 5 - 20 = 80$
$(x + 4) \times 5 = 100$
$(x + 4) = 100 \div 5$
$x + 4 = 20$
$x = 20 - 4$
$x = 16$