Question

4 kg of a metal contains 1/5 copper and rest in Zinc. Another 5 kg of metal contains 1/6 copper and rest in Zinc.The ratio of Copper and Zinc into the mixture of these two metals:

Answer 1

Amount of copper in first sample $=\frac{1}{5}\times 4kg$ $=800gm$

So Amount of zinc in first sample = $3200$ gm

Amount of copper in second sample = $\frac{5000}{6}$gm

So Amount of zinc in second sample = $5000\times \frac{5}{6}$

Total copper in both mixtures = $\frac{9800}{6}$gm

Total zinc in both mixtures = $\frac{44200}{6}$

Thus Ratio of copper to zinc = $49:221$