Question 24
4 L of 0.02 M aqueous solution of NaCl was diluted by adding 1 L of water. The molality of the resultant solution is ........ .
(a) 0.004 (b) 0.008 (c) 0.012 (d) 0.016
(d) Given M1=0.02M V1=4L, M2=? V2=4L+1L=5LAs we know, M1V1=M2V2 0.02×4L=M2×5L M2=0.085=0.016M