Question

4 men and 6 women finish a job in 8 days while 3 men and 7 women finish it in 10 days. In how many days will 10 women working together finish it ?

Answer 1

Let 1 man's 1 day work = $x$ and 1 woman's 1 days work = $y.$

Then $4x+6y$= $\frac{1}{8}$ and $3x+7y$ = $\frac{1}{10}$

On solving we get y = $\frac{1}{400}$

[means work done by a woman in 1 day] 10 women 1 day work = $\frac{10}{400}$ = $\frac{1}{40}$

10 women will finish the work in 40 days