Question

$4$ moles $CO,5$ mole $N_2$ and $2$ mole $C_2{H}_4$ are placed in a $5$ litre at ${27}^{o}C$. The ratio of kinetic energy per molecular of $C{O}_2$, $He$ and $N{H}_3$ is:

• A. $4:5:2$
• B. $5:5:4$
• C. $2:4:5$
• D. $1:1:1$

Answer 1

The correct option is A $4:5:2$

Kinetic energy$=\frac{3}{2}nRT$

Where n, R and T is number of moles, gas constant and temperature respectively

For 4 moles $CO$

KE$=\frac{3}{2}\times 4RT$

For 5 Mole of $N_2$

KE$=\frac{3}{2}\times 5RT$

For 2 mole of $C_2{H}_4$

KE$=\frac{3}{2}\times 2RT$

$CO:N_2:C_2{H}_4=4:5:2$