Question

$4$ moles $CO,5$ moles $N_2$ and $2$ mole $C_2{H}_4$ are placed in a $5$ litre vessel at ${27}^{o}C$. The ratio of kinetic energy per molecule of $C{O}_2,He$ and $N{H}_3$ is?

• A. $4:5:2$
• B. $5:5:4$
• C. $2:4:5$
• D. $1:1:1$

Answer 1

Answer: (D)

$1:1:1$

Kinetic energy per molecule $=\frac{3}{2}RT$

means kinetic energy is depend on Temperature

$\begin{array}{cc}given\stackrel{}{=}& 4\text{moles}CO\\ & 5\text{moles}{N}_2\\ & 2\text{mole}{C}_2{H}_4\end{array}$$\{\begin{array}{c}v=5litre\\ T={27}^{\circ }C\end{array}$

$\begin{array}{cc}\text{Shaw Ratio of}K.E& =CO:N_2:C_2{H}_4\\ & =1:1:1\end{array}$

$\because$ Temperature is same for all molecules.

Correct Answer $=D$