Question

4 moles of an ideal gas $(\gamma =1.67)$ are mixed with 2 moles of another ideal gas $(\gamma =1.40)$. Find the equivalent $\gamma$ for the mixture.

• A. 1.67
• B. 1.55
• C. 1
• D. 1.58

Answer 1

Answer: (B)

1.55

The equivalent $\gamma$ for the mixture is $\frac{4\times 1.67+2\times 1.40}{4+2}=1.55$