4 moles of an ideal gas - - 1-67 are mixed with 2 moles of another ideal gas - - 1-40- Find the equivalent - for the mixture-

The correct option is A 1.55The equivalent γ for the mixture is 4 × 1.67 + 2 × 1.404+2=1.55 ...

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Standard X

Physics

Principle of Calorimetry

4 moles of an...

Question

4 moles of an ideal gas $(γ = 1.67)$ are mixed with 2 moles of another ideal gas $(γ = 1.40)$ . Find the equivalent $γ$ for the mixture.

1.67

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1.55

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1.58

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Solution

The correct option is A 1.55
The equivalent $γ$ for the mixture is $\frac{4 \times 1.67 + 2 \times 1.40}{4 + 2} = 1.55$

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4 moles of an ideal gas (γ=1.67) are mixed with 2 moles of another ideal gas (γ=1.40). Find the equivalent γ for the mixture.

The correct option is A 1.55The equivalent γ for the mixture is 4×1.67+2×1.404+2=1.55

4 moles of an ideal gas $(γ = 1.67)$ are mixed with 2 moles of another ideal gas $(γ = 1.40)$ . Find the equivalent $γ$ for the mixture.

The correct option is A 1.55
The equivalent $γ$ for the mixture is $\frac{4 \times 1.67 + 2 \times 1.40}{4 + 2} = 1.55$