Question

$4$ pencils have the same value of $3$ pens.

One pen is $\frac{1}{3}$the cost of stapler.

Two staplers are worth $3$ packets of notecards.

How many pencils are worth one packets?

Express your answer as a common fraction.

Answer 1

Forming the equation according to question:

Let pencils denoted by $P$, pens is denotes is $Q$, the stapler is denoted by $S$ and packet of notecard is denoted by $N$

$$\begin{gathered} 4P=3Q....\left(i\right) \\ 1P=\frac{1}{3}S..\left(ii\right) \\ 2S=3N...\left(iii\right) \end{gathered}$$

$$\begin{gathered} \Rightarrow N=\frac{2}{3}S \\ \Rightarrow N=\frac{2}{3}\times 3Pfrom\left(ii\right) \\ \Rightarrow N=2P \end{gathered}$$

Hence, the required answer is $2$ pencils.