Question

$4R{N}^2=P{Q}^2+4P{R}^2$
State whether the above statement is true or false.

• A. True
• B. False

Answer 1

The correct option is B False

Given : PQR is right triangle at Q. M and N are mid points of QR and PQ respectively.
Now, In $△NQR$,
$R{N}^2=Q{R}^2+N{Q}^2$ (By Pythagoras theorem)
$R{N}^2=Q{R}^2+(\frac{PQ}{2}{)}^2$ (N is mid point of PQ)
$4R{N}^2=4Q{R}^2+P{Q}^2$