Suppose the cost of 1 table =x and cost of 1 chair =y
Then according to the question
⇒4x+3y=2250...........(1)
⇒3x+4y=1950.............(2)
Multiply (1) by 4 and (2) by 3 and Subtract both
⇒(16x+12y=9000)−(9x+12y=5850)
⇒7x=3150⇒x=450
Put x=450 in eq2
⇒450×4+3y=2250⇒3y=2250−1800⇒3y=450
⇒y=150
Cost of 1 table =450
Cost of 1 chair =150
∴ Cost of 1 table and 2 chair =450+150×2=750