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Question

4. tan 3)4. tan-V3)

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Solution

The inverse of a function f:AB exists if f is one-one onto i.e.,

y=f( x ) f 1 ( y )=x .

The given inverse trigonometry function is tan 1 ( 3 ) .

Let,

tan -1 ( 3 )=y

tany= 3 =tan π 3 =tan( π 3 )

Since, the range of the principle value branch of tan -1 is ( π 2 , π 2 ) .

π 3 ( π 2 , π 2 )

Thus, the principle value of tan 1 ( 3 ) is ( π 3 ) .


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