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Question

4. The radius of a sphere is measured as ( 10 ± 0.02%)cm. The error in the measurement of its volume is

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Solution

Dear student,

The volume of sphere is V=43πr3

Taking log on both side
logV=log43+3log RDiffrentiating on both sidesVV=0+3RRRR=0.02%Then VV=3×0.02=0.06%

Regards.

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