Question 63 4 - 105-3 - 104-2 - 103-1 - 100 -432010

Name: EXEMP - Grade 07 - MATHEMATICS - Exponents & Powers - Q63
Uploaded: 2022-07-04T10:36:42+05:30
Description: False Taking LHS =(4 × 10^5)+(3 × 10^4)+(2 × 10^3)+(1 × 10^0) =(4 × 100000) + (3 × 10000) +(2 × 1000)+ (1 × 1) =400000+30000+2000+1 =432001 ≠RHS Hence, LH ...

False Taking LHS =(4 × 10^5)+(3 × 10^4)+(2 × 10^3)+(1 × 10^0) =(4 × 100000) + (3 × 10000) +(2 × 1000)+ (1 × 1) =400000+30000+2000+1 =432001 ≠RHS Hence, LH ...

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Byju's Answer

Standard VII

Mathematics

Expanding a Rational Number Using Powers

Question 63 4...

Question

Question 63

$4 \times 10^{5} + 3 \times 10^{4} + 2 \times 10^{3} + 1 \times 10^{0} = 432010$

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Solution

False
Taking LHS
$= (4 \times 10^{5}) + (3 \times 10^{4}) + (2 \times 10^{3}) + (1 \times 10^{0}) = (4 \times 100000) + (3 \times 10000) + (2 \times 1000) + (1 \times 1) = 400000 + 30000 + 2000 + 1 = 432001 \neq RHS Hence, LHS \neq RHS$

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Question 61

$876543 = 8 \times 10^{5} + 7 \times 10^{4} + 6 \times 10^{3} + 5 \times 10^{2} + 4 \times 10^{1} + 3 \times 10^{0}$

Q. Find the number from each of the following expanded forms:
(i) 7 × 10⁴ + 6 × 10³ + 0 × 10² + 4 × 10¹ + 5 × 10⁰
(ii) 5 × 10⁵ + 4 × 10⁴ + 2 × 10³ + 3 × 10⁰
(iii) 9 × 10⁵ + 5 × 10² + 3 × 10¹
(iv) 3 × 10⁴+ 4 × 10² + 5 × 10⁰

Write the numeral whose expanded form is given below:
(i) $6 \times 10^{4} + 3 \times 10^{3} + 0 \times 10^{2} + 7 \times 10^{1} + 8 \times 10^{0}$
(ii) $9 \times 10^{6} + 7 \times 10^{5} + 0 \times 10^{4} + 3 \times 10^{3} + 4 \times 10^{2} + 6 \times 10^{1} + 2 \times 10^{0}$
(iii) $8 \times 10^{5} + 6 \times 10^{4} + 4 \times 10^{3} + 2 \times 10^{2} + 9 \times 10^{1} + 6 \times 10^{0}$