4- 105-5- 103-3- 102-2- 102-

y=4× 10^5+5× 10^3+3× 10^2+2× 10^2 y=4000× 10^2+50× 10^2+3× 10^2+2× 10^2 y=(4000+50+3+5)× 10^2 y=4058× 10^2 [y=405800] . ...

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Standard VII

Mathematics

Powers and Exponents

4× 105+5× 103...

Question

$4 \times 10^{5} + 5 \times 10^{3} + 3 \times 10^{2} + 2 \times 10^{2} =$

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Solution

$y = 4 \times 10^{5} + 5 \times 10^{3} + 3 \times 10^{2} + 2 \times 10^{2}$
$y = 4000 \times 10^{2} + 50 \times 10^{2} + 3 \times 10^{2} + 2 \times 10^{2}$
$y = (4000 + 50 + 3 + 5) \times 10^{2}$
$y = 4058 \times 10^{2}$
$[y = 405800]$ .

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Similar questions

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(b) 4 × 10⁵+ 5 × 10³+ 3 × 10²+ 2 × 10⁰

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Q. Find the number from the expanded form:

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Question 61

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4×105+5×103+3×102+2×102=

y=4×105+5×103+3×102+2×102y=4000×102+50×102+3×102+2×102y=(4000+50+3+5)×102y=4058×102[y=405800].

$4 \times 10^{5} + 5 \times 10^{3} + 3 \times 10^{2} + 2 \times 10^{2} =$

$y = 4 \times 10^{5} + 5 \times 10^{3} + 3 \times 10^{2} + 2 \times 10^{2}$
$y = 4000 \times 10^{2} + 50 \times 10^{2} + 3 \times 10^{2} + 2 \times 10^{2}$
$y = (4000 + 50 + 3 + 5) \times 10^{2}$
$y = 4058 \times 10^{2}$
$[y = 405800]$ .