4 - 43-512-84-32 - 84-2 - 2-4

The correct option is C 6Here, (4 × 4)^3 ÷ (512 ÷ 8)^4 × (32 × 8)^4 = (2 × 2)^? 4 ⇒ (16)^3 ÷ (64)^4 × (256)^4 = (4)^? + 4 ⇒ (4)^2 × 3÷ (4^4)^4 × (4^5)^4 = (4 ...

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4 × 43+512+84...

Question

$(4 \times 4)^{3} + (512 + 8)^{4} \times (32 \times 8)^{4} = (2 \times 2)^{? + 4}$

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Solution

The correct option is C 6
$H e r e, (4 \times 4)^{3} \div (512 \div 8)^{4} \times (32 \times 8)^{4} = (2 \times 2)^{? - 4} \Rightarrow (16)^{3} \div (64)^{4} \times (256)^{4} = (4)^{? + 4} \Rightarrow (4)^{2 \times 3} \div (4^{4})^{4} \times (4^{5})^{4} = (4)^{? + 4} \Rightarrow 4^{6 - 16 + 20} = (4)^{? + 4} \Rightarrow ? + 4 = 10 \Rightarrow ? = 6$

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(4×4)3+(512+8)4×(32×8)4=(2×2)?+4

The correct option is C 6Here,(4×4)3÷(512÷8)4×(32×8)4=(2×2)?−4⇒(16)3÷(64)4×(256)4=(4)?+4⇒(4)2×3÷(44)4×(45)4=(4)?+4⇒46−16+20=(4)?+4⇒?+4=10⇒?=6

$(4 \times 4)^{3} + (512 + 8)^{4} \times (32 \times 8)^{4} = (2 \times 2)^{? + 4}$