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Question

(4+x^2-4x)+25 = (4+x^2+4x)+81 can you please explain in detail please and don't show in short please

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Solution

4+x^2-4x+25=4+x^2+4x+81 (opening the brackets)
-4x+25+x^2+4-x^2-4=4x+81 (transposing x^2 and 4)
-4x+25=4x+81 (x^2 and 4 cancelled because of opposite signs)
8x+56=0 (transposing -4x and 25)
8x=-56 (transposing 56)
x=-56/8 (dividing both the sides by 8 to get x)
x=-7 (Answer)

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