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Question

40 30 3600
15 24 17
What will be the sum of the two resultant numbers of the sets of numbers given above?

A
22
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B
25
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C
28
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D
42
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Solution

The correct option is B 25
For Row 1 of numbers
As an even number is followed by a two digit even number, then the second number is multiplied with the first. therefore, 40 multiplied by 30 =1200
Now this 1200, even number is followed by a perfect square 3600 then the second number is divided by 1200. Therefore, the resultant number is 3600 divided by 1200 i.e. 3
For Row 2 of numbers
As an odd number is followed by a two digit even number, then the numbers are added therefore, 15+24=39
This odd number is followed by a two digit odd number 17, then the second number is to be subtracted from the first =39-17=22
Resultant of first set of numbers is added to second i.e. 3+22 =25.
Answer is Option B

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