Step 1: For 40 and 240, we apply division lemma. 248 = 40×6 + 8 The remainder 8≠0. Step 2: For 8 and 40, we apply division lemma. 40 = 8×5 + 0 The remainder ...

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Standard IX

Mathematics

Method of Finding HCF

40 and 248

Question

40 and 248

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Solution

Step-1:- For 40 and 240, we apply division lemma.

248 = 40 $\times$ 6 + 8
The remainder 8 $\neq$ 0.
Step-2:- For 8 and 40, we apply division lemma.

40 = 8 $\times$ 5 + 0
The remainder is 0.
Hence, the HCF of 40 and 248 is 8.

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40 and 248

Step-1:- For 40 and 240, we apply division lemma. 248 = 40×6 + 8 The remainder 8≠0. Step-2:- For 8 and 40, we apply division lemma. 40 = 8×5 + 0 The remainder is 0. Hence, the HCF of 40 and 248 is 8.

Step-1:- For 40 and 240, we apply division lemma.

248 = 40 $\times$ 6 + 8
The remainder 8 $\neq$ 0.
Step-2:- For 8 and 40, we apply division lemma.

40 = 8 $\times$ 5 + 0
The remainder is 0.
Hence, the HCF of 40 and 248 is 8.