40. Calculate the time period of a simple pendulum whose length is equal to radius of earthHint : L = Re = 6.4 × 106 m, g = 9.8 ms-2

Open in App

Solution

Suggest Corrections

Similar questions

Q. Calculate the time period of a simple pendulum of length

1.12 m

, when acceleration due to gravity is

9.8 m s^{- 2}

A simple pendulum of length 40 cm is taken inside a deep mine. Assume for the time being that the mine is 1600 km deep. Calculate the time period of the pendulum there. Radius of the earth = 6400 km.

Q. If mass and radius of the Earth are

6.0 \times 10^{24} k g

and

6.4 \times 10^{6} m

respectively. Calculate the force exerted by the Earth on a body of mass 1 kg, acceleration of the body of mass 1 kg and acceleration of the Earth in order.
Use

G = 6.67 \times 10^{- 11} N m^{2} k g^{- 2}

Q. If the length of a simple pendulum is equal to the radius of the earth, its time period will be

Q. A simple pendulum has a time period of T

_{0}

on the surface of the earth. On another planet whose density is same that of earth but radius is 4 times then time period of this simple pendulum would be :

Join BYJU'S Learning Program