$40 c o u l o m b s$ of charge is brought from infinity to a given point in an electric field when $60 j o u l e s$ of work is done. What is the potential at that point?

Open in App

Solution

Step 1: Given data and formula
Given data:
Charge is $Q = 40 C$
Work done in moving $40 C$ charge is $W = 60 J$
Formula:
If $W$ is the work done in moving a charge $(Q)$ from infinity to a point then the electric potential $(V)$ at that point is given by
$V = \frac{W}{Q}$
Step 2: Finding the electric potential at that point
Substituting the values of $W$ and $Q$ into the equation given in step 1 to calculate the electric potential.
$V = \frac{60 J}{40 C} V = 1.5 V$
Thus, the electric potential at that point is $1.5 V$

Suggest Corrections

Similar questions

Q. A charged sphere of diameter 4 cm has a charge density of

10^{- 4} C / {c m}^{2}

. The work done in joules when a charge of 40 nano-coulombs is moved from infinity to a point, which is at a distance of 2cm from the surface of the sphere is:

When a particle carrying a charge of $10 \times 10^{- 6} coulombs$ is brought from infinity to a point P, $2 \times 10^{- 3} joules$ of work is done. What is the potential at the point P?

Q. Find the electric potential of a point if 2j of work is done in bringing a charge of 0.2 coulomb from infinity to that point

Q. The work done in moving 5 coulombs of charge between two points in an electric field is 30 joule. Calculate the potential difference between the two points.

Q. If

1 J

of work is done in bringing

1 C o u l o m b

of positive charge from infinity to a point in the electric field, then the potential of that point is:

Join BYJU'S Learning Program

40coulombs of charge is brought from infinity to a given point in an electric field when 60joules of work is done. What is the potential at that point?

$40 c o u l o m b s$ of charge is brought from infinity to a given point in an electric field when $60 j o u l e s$ of work is done. What is the potential at that point?