40. Find the remainder when 163+173+183+193 is divided by 70?
(c) 0
Ans 40: (c) Sol: We know that: a3+ b3 = (a+b) (a2 – ab + b2); Clubbing 16 & 19 together and 17 & 18 together, (a+b) in both the cases becomes 35. Now, the other bracket in total has odd number in each of them respectively, hence when added, odd+odd = even. Thus the numerator is an even multiple of 35. Therefore, the remainder will be 0.