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Question

40. Find the remainder when 163+173+183+193 is divided by 70?


A

(a) 1

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B

(b) 2

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C

(c) 0

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D

(d) 3

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Solution

The correct option is C

(c) 0


Ans 40: (c) Sol: We know that: a3+ b3 = (a+b) (a2 – ab + b2); Clubbing 16 & 19 together and 17 & 18 together, (a+b) in both the cases becomes 35. Now, the other bracket in total has odd number in each of them respectively, hence when added, odd+odd = even. Thus the numerator is an even multiple of 35. Therefore, the remainder will be 0.


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