40 g of hot water is poured in 100 g of cold water, when temperature of cold water rises by 10oC. If the temperature of hot water is 60oC, calculate the initial temperature of cold water.
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Solution
For Hot water: Mass=40g S.H.C=4.2Jg−1oC−1 InitialTemp.=60oC FinalTemp.=x
△TH=(60−x) for Cold water: Mass=100g S.H.C=4.2Jg−1oC−1 InitialTemp.=? FinalTemp.=x