40 g water at 60 ℃ is poured into a vessel containing 50 g of water at 20 ℃. The final temperature of mixture is 30℃. Calculate the specific heat capacity of the vessel which weighs 200 g. Take specific heat of water $4.2 J g^{- 1} K^{- 1}$ .
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Solution

Write the given quantities-

$s_{w 1} = 4.2 J g^{- 1} K^{- 1}$

$m_{w 1}$ = 40 g, $T_{w 1}$ = 60 ℃

$m_{w 2} = 50 g, T_{w 1}$ = 20 ℃

$m_{v}$ = 200 g, [1 mark]

$m s \times s_{s}$ (T_1- T_f) = $m_{w} \times s_{w}$ (T_f - T_2) \) + M x s x (T_f - T_2)\)

40 x 4.2 x (60 - 30) = 50 x 4.2 x (30 - 20) + 200 s (30 - 20) [2 mark]

On solving we get, s = 1.47 $J g^{- 1} K^{- 1}$

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40 g water at 60 ℃ is poured into a vessel containing 50 g of water at 20 ℃. The final temperature of mixture is 30℃. Calculate the specific heat capacity of the vessel which weighs 200 g. Take specific heat of water 4.2Jg−1K−1. .

Write the given quantities- sw1=4.2Jg−1K−1 mw1 = 40 g, Tw1 = 60 ℃ mw2=50g,Tw1 = 20 ℃ mv = 200 g, [1 mark] ms ×ss (T_1- T_f) = mw ×sw (T_f - T_2) \) + M x s x (T_f - T_2)\) 40 x 4.2 x (60 - 30) = 50 x 4.2 x (30 - 20) + 200 s (30 - 20) [2 mark] On solving we get, s = 1.47 Jg−1K−1

40 g water at 60 ℃ is poured into a vessel containing 50 g of water at 20 ℃. The final temperature of mixture is 30℃. Calculate the specific heat capacity of the vessel which weighs 200 g. Take specific heat of water $4.2 J g^{- 1} K^{- 1}$ .
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